Two charges of # -3 C # and # 4 C# are positioned on a line at points # -3 # and # 4 #, respectively. What is the net force on a charge of # 7 C# at # 6 #?

1 Answer
Mar 12, 2016

Answer:

#F_"net"=60,66*10^9 N#

Explanation:

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#"The force between two charges is given by Coulomb's formula: "#
#F=k*(q_1*q_2)/d^2" "k=9*19^9#
#"The force between A and C is :"F_(AC)" (the blue vector)"#
#"The Force between B and C is :"F_(BC)" (the red vector)"#
#F_(AC)=k((-3)*7)/9^2=-(21k)/81#
#F_(BC)=k*(4*7)/2^2=(28k)/4#
#"Net Force on a charge of 7C:"F_"net"=F_(AC)+F_(BC)#
#F_"net"=-(21k)/81+(28k)/4#
#F_"net"=k(28/4-21/81)#
#F_"net"=2184/324*k#
#F_"net"=6,74*k#
#F_"net"=6,74*9.10^9#
#F_"net"=60,66*10^9 N#