Two charges of # -4 C # and # 3 C# are positioned on a line at points # -5 # and # 6 #, respectively. What is the net force on a charge of # -8 C# at # -2 #?

1 Answer
Jan 14, 2018

Answer:

The net force is #=28.625*10^9N#

Explanation:

The net force between the charges is

#F=k(Q_1Q_3)/r_1^2+k(Q_2Q_3)/r_2^2#

Where #r# is the distance between the charges

The Coulomb Constant is #k=9*10^9Nm^2/C^2#

The charge #Q_1=-4C# at #(-5,0)#

The charge #Q_2=3C# at #(6,0)#

The charge #Q_3=-8C# at #(-2,0)#

The net force is

#F=910^9*(-4*-8)/(3)^2+910^9(3*-8)/(8)^2=28.625*10^9N#

The positive sign indicates that the force is repulsive