Question

Two charges of `6 C` and `-3 C` are at points `(-2 ,4,-3 )` and `( -8 ,6,1 )`, respectively. Assuming that both coordinates are in meters, what is the force between the two points?

Answer 1

`F=-3*10^9 N " attractive force"`

Explanation:

`"distance between P_1(-2,4,-3) and P_2(-8,6,1) is given by:"` `r^2=(-8+2)^2+(6-4)^2+(1+3)^2`
`r^2=36+4+16`
`r²=56`
`F=(k*q_1*q_2)/r^2`
`F=(cancel(9)*10^9*cancel(6)*(-3))/cancel(56)`
`F=-3*10^9 N " attractive force"`