Question

Two charges of `-6 C` and `4 C` are positioned on a line at points `-5` and `-2`, respectively. What is the net force on a charge of `3 C` at `1`?

Answer 1

`F_(3C)=7,5*10^9 " N"`

Explanation:

`"distance between -6C and 3C="1-(-5)=6 " m"`
`r_1^2=6^2=36`
`"distance between 4C and 3C="(-2)=3 " m"`
`r_2^2=3^2=9`
`"Force between -6C and 3C is attractive:"`
`F_1=(k*(-6)*3)/36`
`F_1=(-18*k)/36`
`"F_1=-k/2`
`"Force between 4C and 3C is:"`
`F_2=(k*4*3)/9`
`F_2=(4*k)/3`
`F_(3C):" Net force acting to charge of 3C"`
`F_(3C)=(4*k)/3-k/2`
`F_(3C)=(8*k-3*k)/6`,
`F_(3C)=(5*k)/6`
`F_(3C)=(5*9*10^9)/6`
`F_(3C)=7,5*10^9 " N"`