# Two charges of  -6 C  and  4 C are positioned on a line at points  -5  and  -2 , respectively. What is the net force on a charge of  -1 C at  1 ?

Feb 13, 2016

pl use the formula F = $\frac{1}{4 \pi \epsilon {r}^{2}} \left(q Q\right)$

#### Explanation:

The -1 C charge is at a distance 6m apart from -6C and 3m apart from 4C. The force of 6C is repulsive and that of 4C is attractive and they are acting on the same line. So magnitude of second one is to be subtracted from first one.