Two charges of  9 C  and  -8 C are positioned on a line at points  -3  and  -1 , respectively. What is the net force on a charge of  7 C at  0 ?

Jan 22, 2018

441×10^9 N

Explanation:

Here,the $9 C$ charge tries to push the $7 C$ charge towards positive direction.

And the value of that force $F 1$ is
(9×10^9)×9×7/(3)^2 N i.e 63×10^9 N

Whereas, the $- 8 C$ charge tries to pull the $7 C$ charge towards its position i.e in negative direction.

And the amount of force $F 2$ is
(9×10^9)×(-8)×7/(-1)^2 N or,504×10^9 N

So,net force acting is towards negative direction and it is $F 2 - F 1$ i.e (504-63)×10^9 N or, 441×10^9 N