Two charges of # 9 C # and # -8 C# are positioned on a line at points # -3 # and # -1 #, respectively. What is the net force on a charge of # 7 C# at # 0 #?

1 Answer
Jan 22, 2018

Answer:

#441×10^9 N#

Explanation:

Here,the #9C# charge tries to push the #7C# charge towards positive direction.

And the value of that force #F1# is
#(9×10^9)×9×7/(3)^2 N# i.e #63×10^9 N#

Whereas, the #-8C# charge tries to pull the #7C# charge towards its position i.e in negative direction.

And the amount of force #F2# is
#(9×10^9)×(-8)×7/(-1)^2 N# or,#504×10^9 N#

So,net force acting is towards negative direction and it is #F2 - F1# i.e #(504-63)×10^9 N# or, #441×10^9 N#