# Two six sided dice are rolled. How do you find the probability that the sum is 3 or 4?

$\frac{7}{36}$

#### Explanation:

The possible rolls of two standard fair dice are below:

$\left(\begin{matrix}\textcolor{w h i t e}{0} & \underline{1} & \underline{2} & \underline{3} & \underline{4} & \underline{5} & \underline{6} \\ 1 | & 2 & 3 & 4 & 5 & 6 & 7 \\ 2 | & 3 & 4 & 5 & 6 & 7 & 8 \\ 3 | & 4 & 5 & 6 & 7 & 8 & 9 \\ 4 | & 5 & 6 & 7 & 8 & 9 & 10 \\ 5 | & 6 & 7 & 8 & 9 & 10 & 11 \\ 6 | & 7 & 8 & 9 & 10 & 11 & 12\end{matrix}\right)$

Out of 36 possible rolls, there are two ways to get a 3 and three ways to get a 4, and so we have:

$P \left(\text{roll of 2 dice sums to 3 or 4}\right) = \frac{3 + 4}{36} = \frac{7}{36}$