# Two students walk in the same direction along a straight path, at a speed-one at 0.90 m/s and the other at 1.90 m/s. Assuming that they start at the same point and the same time, how much sooner does the faster student arrive at a destination 780 m away?

##### 1 Answer

The faster student arrives at the destination 7 minutes and 36 secs (approximately) sooner than the slower student.

#### Explanation:

Let the two students be A and B

Given that

i) Speed of A = 0.90 m/s ---- Let this be s1

ii) Speed of B is 1.90 m/s -------Let this be s2

iii) Distance to be covered = 780 m -----let this be

We need to find out the time taken by A and B to cover this distance to know how sooner the faster student arrive at destination. Let the time be t1 and t2 respectively.

The equation for speed is

Speed =

Therefore

Time taken =

Student A takes more time than student B, i.e. B reaches first.

We find the difference t1 - t2

In minutes ------

i.e. 7 minutes and 36 seconds

Answer : Student B reaches the destination 7 minutes 36 seconds (approximately) sooner than student A.

**Note** : all the values are truncated up to two decimal places without rounding.