Under identical condition the rate of effusion of #"CH"_4# is higher than that of A) #"O"_2# b) #"H"_2# c) #"N"_2# d) #"He"# ???
1 Answer
Sep 18, 2017
The rate of effusion is inversely proportional to the square root of its molecular mass..........we get
Explanation:
And this has been empirically verified in
And so the rate of effusion of methane WILL be GREATER than those gases that are more massive, i.e. those who have GREATER molecular mass.....i.e. dioxygen, and dinitrogen, and LESS than those less massive, helium, and diydrogen.....
Good question, because it forces the student to consider all the options, I am stealing it
