#UO_3# reacts with #H^+# ions to produce #UO_2^(2+)# ions and water. Write the balanced equation for this reaction?

please give info on how you did it thanks

1 Answer

#UO_3(s) + 2 H^+(aq) -> UO_2^(2+)(aq) + H_2O(l)#

Explanation:

Placing all the terms given into an equation:

#UO_3 + H^+ -> UO_2^(2+) + H_2O #

As you can see, the equation is not balanced yet:

  • Left hand side has 1 H while right hand side has 2 H
  • total charge on the left is +1, while on the right it's +2

To fix this, let's place a 2 in front of #H^+#.

#UO_3 + 2 H^+ -> UO_2^(2+) + H_2O #

That balanced the number of H on both sides, as well as the total charge (+2).

Putting in the physical states:
#UO_3(s) + 2 H^+(aq) -> UO_2^(2+)(aq) + H_2O(l) #