# UO_3 reacts with H^+ ions to produce UO_2^(2+) ions and water. Write the balanced equation for this reaction?

## please give info on how you did it thanks

Jul 24, 2018

$U {O}_{3} \left(s\right) + 2 {H}^{+} \left(a q\right) \to U {O}_{2}^{2 +} \left(a q\right) + {H}_{2} O \left(l\right)$

#### Explanation:

Placing all the terms given into an equation:

$U {O}_{3} + {H}^{+} \to U {O}_{2}^{2 +} + {H}_{2} O$

As you can see, the equation is not balanced yet:

• Left hand side has 1 H while right hand side has 2 H
• total charge on the left is +1, while on the right it's +2

To fix this, let's place a 2 in front of ${H}^{+}$.

$U {O}_{3} + 2 {H}^{+} \to U {O}_{2}^{2 +} + {H}_{2} O$

That balanced the number of H on both sides, as well as the total charge (+2).

Putting in the physical states:
$U {O}_{3} \left(s\right) + 2 {H}^{+} \left(a q\right) \to U {O}_{2}^{2 +} \left(a q\right) + {H}_{2} O \left(l\right)$