# Upon heating, calcium carbonate decomposes to produce calcium oxide and carbon dioxide. What is the theoretical yield of CO_2 if 235.0 g CaCO_3 is heated?

Mar 17, 2016

Approx. 100 g of carbon dioxide gas are evolved.

#### Explanation:

$C a C {O}_{3} \left(s\right) + \Delta \rightarrow C a O \left(s\right) + C {O}_{2} \left(g\right) \uparrow$

There is thus a 1:1 molar equivalence of carbonate to carbon dioxide.

$\text{Moles of calcium carbonate}$ $=$ $\frac{235.0 \cdot g}{100.0869 \cdot g \cdot m o {l}^{-} 1}$ $=$ $2.35$ $m o l$.

So, by reaction stoichiometry, $2.35$ $m o l$ $C {O}_{2} \left(g\right)$ are evolved.

If conversion is quantitative, there are $2.35$ $m o l$ $\times$ $44.0 \cdot g \cdot m o {l}^{-} 1$ $C {O}_{2}$ $=$ ??g