Question

Urgent. Please help. Calculate the percentage uncertainty for the displacement when t = 40s?

Answer 1

See below:

Explanation:

when `t=40`, `x approx 3 cm`

Each square in the vertical direction represents 0.4 cm (from my point of view), so the bar stretches approximately across 0.5 cm.

So the percentage uncertainty is, therefore:

`0.5/3.0 approx 0.167 times 100=17%` (two sig.figs)