Use FOIL to solve the problem (x²+y)(x²-y) inner ?

Question

2723 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-02-13T02:02:21

#(x^2+y)(x^2-y)=x^4-y^2#

We will apply the F.O.I.L method

#overbrace((x^2)(x^2))^"First"+overbrace((x^2)(-y))^"Outside"+overbrace((y)(x^2))^"Inside"+overbrace((y)(-y))^"Last"#

This will give us:

#x^4-x^2y+x^2y-y^2#

The middle terms will cancel and so we are left with

#x^4-y^2#

Answer 2 · 2018-02-13T02:02:53

#x^4-y^2#

Distribute using FOIL: (First, Last, Inner, Last).

#(x^2+y)*(x^2-y)#

#x^4-x^2y+x^2y-y^2#

#x^4-y^2#

The answer is #x^4-y^2#

Hope this helps!