Use FOIL to solve the problem (x²+y)(x²-y) inner ?

2 Answers
Feb 13, 2018

#(x^2+y)(x^2-y)=x^4-y^2#

Explanation:

We will apply the F.O.I.L method

#overbrace((x^2)(x^2))^"First"+overbrace((x^2)(-y))^"Outside"+overbrace((y)(x^2))^"Inside"+overbrace((y)(-y))^"Last"#

This will give us:

#x^4-x^2y+x^2y-y^2#

The middle terms will cancel and so we are left with

#x^4-y^2#

Feb 13, 2018

#x^4-y^2#

Explanation:

Distribute using FOIL: (First, Last, Inner, Last).

#(x^2+y)*(x^2-y)#

#x^4-x^2y+x^2y-y^2#

#x^4-y^2#

The answer is #x^4-y^2#

Hope this helps!