# Use the solubility curve?

Well, you lines up the $y - \text{ordinate}$ with the $x - \text{abscissa}$.
And so using the graph, we could make a saturated solution of $K C l$ in water by dissolving $44 \cdot g$ to $100 \cdot m L$ to water......
At $10$ ""^@C the least soluble substance is $\text{potassium chlorate}$, $K C l {O}_{3}$.
As is typical, SOLUBILITY of a solid solute INCREASES with INCREASING TEMPERATURE. And the SOLUBILITY of a gaseous solute DECREASES with INCREASING TEMPERATURE (interrogate the solubilities of $\text{ammmonia}$, $\text{sulfur dioxide}$, and $\text{hydrogen chloride}$). And this can be rationalized in that when we dissolve a solid, we have to supply energy to BREAK the solute-solute bonds.