Use the suggested substitution to write the expression as a trigonometric expression. Please help.?

Question

#sqrt(x^2-9) , x = 3csc (θ)#

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Answer 1 · 2018-02-22T03:15:35

3cotθ

#sqrt((3cscx)^2-9)=#
#sqrt(9csc^2x-9)=#
#sqrt(9(csc^2x-1))=#
#sqrt(9(cot^2x))=#
#3cotx#