# Using algebra, how do you find the smallest three consecutive integers whose sum is greater than 20?

##### 1 Answer

Nov 16, 2016

Find that the three integers are:

#### Explanation:

Suppose the middle consecutive integer is

Then we want:

#20 < (n-1) + n + (n+1) = 3n#

Dividing both ends by

#n > 20/3 = 6 2/3#

So the smallest integer value of