# Using Newton's method, a root of #x^3+3x+7=0# correct to one decimal place is: A. x=1.6 B. x=1.5 C. x=1.4 D. x=1.3 Help please?

##### 1 Answer

Oct 7, 2017

The answer is option

#### Explanation:

The Newton's method : To obtain successive approximations of

Here,

Let

Therefore,

graph{x^3+3x+7 [-7.56, 4.92, -2.27, 3.97]}