Using Positive Exponents, how do you solve the following problems?
1 Answer
2x^4y^3 625a^8b^16 16777216x^30y^24 1
Explanation:
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(12x^7y^11)/(6x^3 y^8)
Since everything on the numerator and denominator is multiplication, you simply divide like terms. Whenx^3 is divided byx , that is the same as(x*x*x)/x . Thex in the denominator cancels out one of thex 's in the numerator, leavingx^2 . This implies that the exponent 1 in the denominator was subtracted from the exponent 3 in the numerator, leaving an exponent of 2:x^2 .
By this process,x^7/x^3=x^4 andy^11/y^8=y^3
For the coefficients,12/6 =2 .
Combined, that is2x^4y^3 -
(5a^2b^4)^4
(5a^2b^4)^4=(5a^2b^4)*(5a^2b^4)*(5a^2b^4)*(5a^2b^4)
When you raise an exponent to an exponent, the exponents multiply. The coefficient in the equation is also raised the to exponent. Thus,
(5a^2b^4)^4=5^4*a^(2*4)*b^(4*4)=625a^8b^16 -
(4^2x^5y^4)^6=(16x^5y^4)^6=16777216x^30y^24 -
32^0
Any number (except 0) raised the the power of 0 is 1.
32^0=1