Using the equation #2"Al"(s) + 3"H"_2"SO"_4(aq) -> "Al"_2("SO"_4)_3(aq) + 3"H"_2(g)#. Starting with #15.0# moles of #"Al"#, determine the theoretical yield of #"H"_2# ?

1 Answer
Feb 26, 2018

Answer:

#"22.5 moles H"_2#

Explanation:

You first find the ratio between your unknown and your known, unknown on top and known on the bottom.

So with this question, your unknown is #"H"_2# and your known is #"Al"#. Your ratio is #3/2#.

Then, you take the number of moles of your known, #15# moles of #"Al"#, and multiply it by that ratio and you get the number of moles of your unknown, which in this case is #22.5# moles of #"H"_2#

#"15 mol Al" * "3 mol H"_2/"2 mol Al" = "22.5 mol H"_2#