# Using the equation 2"Al"(s) + 3"H"_2"SO"_4(aq) -> "Al"_2("SO"_4)_3(aq) + 3"H"_2(g). Starting with 15.0 moles of "Al", determine the theoretical yield of "H"_2 ?

Feb 26, 2018

${\text{22.5 moles H}}_{2}$

#### Explanation:

You first find the ratio between your unknown and your known, unknown on top and known on the bottom.

So with this question, your unknown is ${\text{H}}_{2}$ and your known is $\text{Al}$. Your ratio is $\frac{3}{2}$.

Then, you take the number of moles of your known, $15$ moles of $\text{Al}$, and multiply it by that ratio and you get the number of moles of your unknown, which in this case is $22.5$ moles of ${\text{H}}_{2}$

${\text{15 mol Al" * "3 mol H"_2/"2 mol Al" = "22.5 mol H}}_{2}$