Dear friends, Please read our latest blog post for an important announcement about the website. ❤, The Socratic Team

Using the first principles, find the derivative of #y=(3-x)/sqrt(2-x)# at x=-2?

1 Answer
Write your answer here...
Start with a one sentence answer
Then teach the underlying concepts
Don't copy without citing sources
preview
?

Answer

Write a one sentence answer...

Answer:

Explanation

Explain in detail...

Explanation:

I want someone to double check my answer

Describe your changes (optional) 200

1
Jun 19, 2018

Answer:

there is no derivative at that point: infinity by one side, out of domain by the other side

Explanation:

#y = (3 - x)(2 - x)^(-1/2)#

#y' = (-1) (2 - x)^(-1/2) + (3 - x) (-1/2)(2 - x)^(-3/2)(-1)#

#y' = - 1 / (2 - x)^(1/2) + (3 - x) / (2 * (2 - x)^(3/2))#

#y' = (-2* (2 - x)+ 3 - x) / (2 * (2 - x)* (2 - x)^(1/2))#

#y' = (x - 1) / (2 * (2 - x)* sqrt(2 - x))#

Was this helpful? Let the contributor know!
1500