# We have a propane molecule that lost a H and gains the OH- functional group. What have we created? How is the charge different for this molecule?

So you start with ${H}_{3} C - C {H}_{2} C {H}_{3}$, you finish ${H}_{3} C - C {H}_{2} C {H}_{2} O H$ or ${H}_{3} C - C H \left(O H\right) C {H}_{3}$, $\text{n-propanol}$ or $\text{isopropanol}$.