We have a propane molecule that lost a H and gains the OH- functional group. What have we created? How is the charge different for this molecule?

1 Answer
anor277
Aug 28, 2016

You have created an alcohol!

Explanation:

So you start with #H_3C-CH_2CH_3#, you finish #H_3C-CH_2CH_2OH# or #H_3C-CH(OH)CH_3#, #"n-propanol"# or #"isopropanol"#.

The alkane and the daughter alcohols molecules are neutral species. The alcohols are a little bit more polar and would have some considerable water solubility.

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