Weight of a body of mass M decreases by 1% when it is raised to a height h above the Earth surface if the body is taken to a depth age in a mine then its weight will decrease by what percent?

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Answer 1 · 2018-04-02T18:47:57

The weight will decrease by #=0.5%#

The weight is #=Mg#

But

#g=(GM)/r^2#

Then

#g_h=(GM)/(r+h)^2#

#g/(g_h)=100/99=((r+h)/r)^2#

#(r+h)/r=sqrt(100/99)=1.005#

#r+h=1.005r#

#h=0.005r#

#g_d=g(1-d/r)#

#(gd)/(g)=1-d/r#

#d=0.005r#

#g_d=1-0.005=0.995#

The weight will decrease by #=0.5%#