# What acceleration will you give to a 27.7 kg box if you push it with a force of 86.1 N, in terms of meter per seconds squared?

Nov 5, 2015

$3.11 \frac{m}{s} ^ 2$

#### Explanation:

Assuming there is no friction or other forces acting on the box, we can simply apply Newton's 2nd law.
$F = m a$

In this case we know the force ($F$) and the mass ($m$). So we just need to solve for the acceleration ($a$).

$a = \frac{F}{m}$

$a = \frac{86.1 N}{27.7 k g} = 3.11 \frac{m}{s} ^ 2$