# What amount of atoms, in mol, is present in 128g of sulfur dioxide? Why?

## Between the optional answer I have : A. 1.2 X ${10}^{24}$ B. 3.6 x ${10}^{24}$ C. 2 D. 6 I know that the answer is 6, I just don't know/ understand why?

Feb 17, 2016

I know how to show that the answer is D.

#### Explanation:

I know that the answer is 6,

The reason is that if we divide 128 g by the molar mass of sulfur dioxide we get $\frac{128}{\text{64,066}}$ = 2 moles of molecules.

Each molecule of ${\text{SO}}_{2}$ contains 3 atoms, so each mole of ${\text{SO}}_{2}$contains 3 mol of atoms.

2 color(red)(cancel(color(black)("mol of molecules"))) × "3 mol of atoms"/(1 color(red)(cancel(color(black)("mol of molecules")))) = "6 mol of atoms"