# What amount of energy is required to melt a 10.7 g piece of ice at 0 C? The heat of fusion of ice = 333 Jg-1

Jul 11, 2017

Approx. $3.5 \cdot k J$...........Why?

#### Explanation:

We perform the physical reaction........

${H}_{2} O \left(s\right) + \Delta \rightarrow {H}_{2} O \left(l\right)$; both reactants and products are at $0$ ""^@C, and thus we need only assess the energy transfer of the PHASE change........

We are given the $\text{heat of fusion}$ of ice in $J \cdot {g}^{-} 1$....

We gots a $10.7 \cdot g$ mass of ice, and so we take the product.........

10.7*cancelgxx333*J*cancel(g^-1)xx10^-3*J*kJ^-1=??J....

And this represents HEAT, $\Delta$, put into the system.........is the sign correct?