What amount of energy is required to melt a 10.7 g piece of ice at 0 C? The heat of fusion of ice = 333 Jg-1

1 Answer
Jul 11, 2017

Answer:

Approx. #3.5*kJ#...........Why?

Explanation:

We perform the physical reaction........

#H_2O(s) +Deltararr H_2O(l)#; both reactants and products are at #0# #""^@C#, and thus we need only assess the energy transfer of the PHASE change........

We are given the #"heat of fusion"# of ice in #J*g^-1#....

We gots a #10.7*g# mass of ice, and so we take the product.........

#10.7*cancelgxx333*J*cancel(g^-1)xx10^-3*J*kJ^-1=??J#....

And this represents HEAT, #Delta#, put into the system.........is the sign correct?