# What angle will the guy wire make with the ground if A tower, 28.4 feet high, must be secured with a guy wire anchored 5 feet from the base of the tower?

Dec 3, 2014

Let $\theta$ be the angle between the wire and the ground.

Since

$\tan \theta = \frac{O}{A} = \frac{28.4}{5}$,

we have

$\theta = {\tan}^{- 1} \left(\frac{28.4}{5}\right) \approx 1.4$ rad $\approx {80}^{\circ}$

I hope that this was helpful.