# What are all the possible rational zeros for #f(x)=5x^3-31x^2+31x-5# and how do you find all zeros?

##### 1 Answer

Dec 11, 2016

#### Explanation:

graph{y-5x^3+31x^2-31x+5=0 [-10, 10, -5, 5]} The sum of the coefficients is 0. So, 1 is a zero for f.

Now,

The zeros of the quadratic factor are

The x-intercepts in the graph give the zeros of f.