What are the asymptotes and removable discontinuities, if any, of #f(x)=( 2x^2 + 3x-2)/(x-2)#?

1 Answer
Apr 13, 2017

Vertical asymptote at #x = 2#
Slant asymptote: #y = 2x+7#
No removable discontinuities

Explanation:

For rational functions #f(x) = (N(x))/(D(x))= (a_nx^n + ...)/(b_mx^m+...)#

Factor the numerator to see if there are any removable discontinuities (holes):

#f(x) = ((2x-1)(x+2))/(x-2)#

Nothing cancels, so No removable discontinuities

Vertical asymptotes found when #D(x) = 0#:
Vertical asymptote at #x = 2#

When #m + 1 = n# you have a slant asymptote:
#m = 1, n= 2" #m + 1 = n = 2# so we have a slant asymptote.

Slant asymptotes are found by polynomial long division or synthetic division:

#f(x) = (2x^2 + 3x - 2)/(x - 2) = 2x + 7 +12/(x-2)#

The slant asymptote: #y = 2x + 7#