What are the asymptotes and removable discontinuities, if any, of #f(x)=(2x^3)/(x+1) #?

1 Answer
Salt²
Jun 22, 2018

vertical asymptote at #x=-1#
no removable discontinuities.

Explanation:

Just set the denominator equal to zero in this case:
#x+1=0#
which solves for
#x=-1#
since the highest exponent in the nummerator is higher this is a pole and doesnt cancel out.

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