What are the asymptotes and removable discontinuities, if any, of #f(x)=(-x^2-2x+15)/( x-5)#?
1 Answer
Explanation:
The denominator of f(x) cannot be zero as this would make f(x) undefined. Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non-zero for this value then it is a vertical asymptote
#"solve "x-5=0rArrx=5" is the asymptote"#
#"Horizontal asymptotes occur if the degree of the " #
#"numerator "<=" to the degree of the denominator"#
#"this is not the case here hence there are no horizontal"#
#"asymptotes"#
#"slant asymptotes occur if the degree of the numerator"#
#>" degree of the denominator"#
#"hence there is a slant asymptote so divide"#
#-x(x-5)-7(x-5)-20#
#rArrf(x)=(-x^2-2x+15)/(x-5)=-x-7-20/(x-5)#
#"as "xto+-oo,f(x)to-x-7#
#rArry=-x-7" is the asymptote"#
graph{(-x^2-2x+15)/(x-5) [-10, 10, -5, 5]}