Question

What are the concentrations of `H_3O^+` and `OH^-` in oranges that have a pH of 3.7?

Answer 1

`[H_3O^+]=10^(-pH)=10^(-3.7)=2.0xx10^(-4)`

Explanation:

`pOH=14-pH=14-3.7=10.3`

`[OH^-]=10^(-10.3)=5.0xx10^-11`

Check your answer!
The product should come out like:
`[H_3O^+][OH^-]=1.0xx10^-14`
(the water constant at room temperature)
And it does.