What are the concentrations of #H_3O^+# and #OH^-# in oranges that have a pH of 3.7?

1 Answer
Dec 26, 2016

Answer:

#[H_3O^+]=10^(-pH)=10^(-3.7)=2.0xx10^(-4)#

Explanation:

#pOH=14-pH=14-3.7=10.3#

#[OH^-]=10^(-10.3)=5.0xx10^-11#

Check your answer!
The product should come out like:
#[H_3O^+][OH^-]=1.0xx10^-14#
(the water constant at room temperature)
And it does.