# What are the conic sections of the following equations 4x ^2 + 4y ^2 - 60=0?

Jun 5, 2018

$4 {x}^{2} + 4 {y}^{2} - 60 = 0$ dividing by 4
${x}^{2} + {y}^{2} - \frac{60}{4} = {x}^{2} + {y}^{2} - 15 = 0$
This is a circle centered in $\left(0 , 0\right)$ and radius $\sqrt{15}$