# What are the critical points of #f(t) = tsqrt(2-t)#?

##### 2 Answers

#### Answer:

The critical points are at t=3/4,2

#### Explanation:

To find the critical points of a function you need to find where the derivative is 0. When the slope is zero there is a horizontal tangent, and thus a maximum or a minimum so a critical feature of the graph.

Derivative:

When finding the derivative do not forget about the product rule and chain rule.

The only time where the derivative is 0 is at t=3/4.

The domain of

So the other critical point would be t=2

#### Answer:

#### Explanation:

Critical points (

**Let's find where f'(t) = 0:**

**Now where it isn't defined (denominator isn't 0):**

**Check both #t=2# and #t = 4/3# are in #f(t)#'s domain.**

Domain of f(t):

**✓**

**✓**

** Answers: #t = 4/3 , t = 2# **