What are the critical points of #f(t) = tsqrt(2-t)#?
The critical points are at t=3/4,2
To find the critical points of a function you need to find where the derivative is 0. When the slope is zero there is a horizontal tangent, and thus a maximum or a minimum so a critical feature of the graph.
The only time where the derivative is 0 is at t=3/4.
The domain of
So the other critical point would be t=2
Critical points (
Let's find where f'(t) = 0:
Now where it isn't defined (denominator isn't 0):
Domain of f(t):