What are the critical points of #f(x)= -x^2 + 3x# on the interval [0,3]?
First of all. You must get the first derivative of f(x) =
The first derivative is
Now you must set
You must also find where
-2x+3 = 0
x = 3/2
Since 3/2 is define in the original function, it is a critical number.
X = 3/2 is not rejected because it exist in the closed interval.