Question

What are the critical points of `f(x) = x^2e^x + 2/x^2`?

Answer 1

There is one critical number. It is approximately #0.873

Explanation:

`f'(x) = 2xe^x+x^2e^x-4/x^3`

Using approximation or technology, we find that

`f'(x) = 0` at about `0.873`