What are the exact values of #cos 150°# and #sin 150°#?

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Nghi N. Share
Jan 9, 2017

Answer:

#cos 150= - sqrt3/2#
#sin 150 = 1/2#

Explanation:

Use trig table and unit circle -->
#cos 150 = cos (-30 + 180) = - cos (-30) =#
# - cos 30 = - sqrt3/2#
#sin 150 = sin (- 30 + 180) = sin 30 = 1/2#

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