What are the excluded values - 7z/4z+1?

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Answer 1 · 2018-04-24T02:56:11

The excluded value is #z=-1/4#.

An excluded value occurs in a fraction when the denominator (the bottom) equals zero, like this:

#(x+2)/(d)#

In this case, #d# cannot be #0#, because that would cause the denominator to be #0#, making the fraction undefined.

In our case, just set the denominator equal to #0# and solve for #z# to find the excluded values.

#-(7z)/(4z+1)#

Set the denominator equal to #0#:

#4z+1=0#

#4z=-1#

#z=-1/4#

That's the only excluded value. Hope this helped!