What are the explicit and recursive formulas for the sequence #6, 10, 14, 18#?

1 Answer
Jul 8, 2018

Explicit formula of the sequence is #T_n= 4 n+2#
Recursive formula is #a_1=6,a_n=a_(n-1)+4 #

Explanation:

Sequence is #S= {6,10,14,18} ; a= 6 , d= 10-6=4#

Explicit formula gives value of the specified term,

#T_n= a+(n-1)d ; a , d , n# are 1st term, common difference

and position of the term. #T_1= 6+(1-1)4=6#, similarly

#T_4= 6+(4-1)4=6+12=18# Therefore explicit formula

of the sequence is #T_n= 6+(n-1)4=4 n+2#

Recursive formula gives value of the specified term based on

previous term. #a_1= 6 , a_n=a_(n-1)+4 :. a_2=a_(2-1)+4#

or #a_2=a_1+4=6+4=10 ; a_3=a_2+4=10+4=14#

and so on. Therefore , recursive formula of the sequence is

#a_1=6,a_n=a_(n-1)+4 # [Ans]