Question

What are the factors of `(9m^2+t^2)` in the set of complex numbers?

Answer 1

`9m^2+t^2 = (3m-ti)(3m+ti)`

Explanation:

We can factor this as a difference of squares using:

`a^2-b^2=(a-b)(a+b)`

with `a=3m` and `b=ti` as follows:

`9m^2+t^2 = (3m)^2-(ti)^2 = (3m-ti)(3m+ti)`