# What are the factors of x^2-5x-24?

Aug 5, 2017

$\left(x - 8\right) \left(x + 3\right)$

#### Explanation:

In the $A {x}^{2} + B x + C$ form of the equation the C is negative which means it must have one negative factor and one positive factor.

The B is negative which means that the negative factor is five greater than the positive factor.

$8 \times 3 = 24$$\textcolor{w h i t e}{\ldots} \mathmr{and} \textcolor{w h i t e}{\ldots}$$8 - 3 = 5$

so the factors that work for 24 are -8 and+ 3

$\left(x - 8\right) \left(x + 3\right) = 0$

The factors are $\left(x - 8\right)$ and $\left(x + 3\right)$