What are the factors of #x^2-5x-24#?

1 Answer

Answer:

#(x -8)( x+3)#

Explanation:

In the # Ax^2 + Bx + C# form of the equation the C is negative which means it must have one negative factor and one positive factor.

The B is negative which means that the negative factor is five greater than the positive factor.

# 8 xx 3 = 24##color(white)(...) andcolor(white)(...)## 8-3 = 5#

so the factors that work for 24 are -8 and+ 3

# ( x-8)(x+3) = 0 #

The factors are #(x-8)# and #(x+3)#