What are the factors of $x^2-5x-24$ ?

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Answer 1 · 2017-08-05T20:40:44

$(x -8)( x+3)$

In the $Ax^2 + Bx + C$ form of the equation the C is negative which means it must have one negative factor and one positive factor.

The B is negative which means that the negative factor is five greater than the positive factor.

$8 xx 3 = 24$ $color(white)(...) andcolor(white)(...)$ $8-3 = 5$

so the factors that work for 24 are -8 and+ 3

$( x-8)(x+3) = 0$

The factors are $(x-8)$ and $(x+3)$

What are the factors of x^2-5x-24x^2-5x-24?