# What are the mean and standard deviation of a binomial probability distribution with n=200 and p=0.3?

Mean $= 60$
standard deviation $= 6.48074$
mean $= n p = 200 \left(.3\right) = 60$
standard deviation $= \sqrt{n p q} = \sqrt{n p \left(1 - p\right)} = \sqrt{60 \left(.7\right)} = 6.48074$