# What are the mean and standard deviation of a binomial probability distribution with n=100  and p=8/10 ?

$P \left(X = k\right) = \left(\begin{matrix}n \\ k\end{matrix}\right) {p}^{k} {\left(1 - p\right)}^{n - k}$
with  mu_(""_(X)) = np = 100*8/10 = 80
sigma_(""_(X))^2 = np(1-p) = 100(8/10)(2/10) = 16