What are the mean and standard deviation of a binomial probability distribution with #n=190 # and #p=7/11 #?

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Answer 1 · 2016-04-27T01:31:15

mean #mu=120 10/11=120.909090#
standard deviation #sigma=6.630757283#

For Binomial Probability Distribution
mean #mu=np# and
standard deviation #sigma=sqrt(npq)#

Given #n=190# and #p=7/11#

Compute the mean:
#mu=np=190*7/11=1330/11=120 10/11=120.909090#

Compute the standard deviation #sigma#

#sigma=sqrt(np(1-p))=sqrt(190*7/11*(1-7/11))#

#sigma=sqrt(190*7/11*(4/11))=(2sqrt(1330))/11#

#sigma=6.630757283#

God bless...I hope the explanation is useful.