What are the mean and standard deviation of a binomial probability distribution with $n=25$ and $p=10/17$ ?

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Answer 1 · 2016-02-12T20:13:02

$mu=250/17~=0.588$
$sigma = sqrt(1750/289)~=2.46$

The following are the equations for the mean and variance of the binomial distribution (taken from Wikipedia: Binomial Distribution )

$mu=n*p$
$Var = n*p*(1-p)$

where $n$ is the number of trials, and $p$ is the probability of success in each trial. Standard Deviation is simply the square root of the variance:

$sigma = sqrt(Var) = sqrt(n*p*(1-p))$

using the values from the question

$mu = 25*10/17 = 250/17 ~=0.588$
$sigma = sqrt(25*10/17*(1-10/289)) = sqrt(1750/289)~=2.46$

What are the mean and standard deviation of a binomial probability distribution with n=25 n=25 and p=10/17 p=10/17 ?