# What are the mean and standard deviation of a binomial probability distribution with n=460  and p=16/23 ?

Dec 26, 2015

$M e a n = 320$
$S D = 9.87$

#### Explanation:

Mean of the Binomial Distribution is -

$M e a n = n p = 460 \times \frac{16}{23} = 320$
$q = 1 - p = 1 - \frac{16}{23} = \frac{7}{23}$
$S D = \sqrt{n p q} = \sqrt{460 \times \frac{16}{23} \times \frac{7}{23}} = \sqrt{97 \frac{9}{23}} = 9.87$