# What are the mean and standard deviation of a binomial probability distribution with n=5  and p=12/17 ?

mean$\cong 3.529411765$
standard deviation$= 1.018853416$
Mean $= n p = 5 \cdot \frac{12}{17} = \frac{60}{17} = 3.529411765$
Standard deviation$= \sqrt{n p q} = \sqrt{n p \left(1 - p\right)} = \sqrt{5 \left(\frac{12}{17}\right) \left(1 - \frac{12}{17}\right)} = 1.018853416$