# What are the mean and standard deviation of a binomial probability distribution with n=4  and p=15/32 ?

Nov 26, 2015

Mean $= 1 \frac{7}{8}$
SD$= 0.998$

#### Explanation:

Given-

$n = 4$
$p = \frac{15}{32}$
$q = 1 - p = 1 - \frac{15}{32} = \frac{17}{32}$

Mean $= n p = 4 \times \frac{15}{32} = 1 \frac{7}{8}$

SD $= \sqrt{n p q} = \sqrt{4 \times \frac{15}{32} \times \frac{17}{32}} = \sqrt{\frac{1020}{1024}} = \sqrt{\frac{255}{256}} = 0.998$