Question

What are the mean and standard deviation of a binomial probability distribution with `n=4` and `p=15/32`?

Answer 1

Mean `=1 7/8`
SD`=0.998`

Explanation:

Given-

`n=4`
`p=15/32`
`q=1-p =1-15/32=17/32`

Mean `=np=4 xx 15/32=1 7/8`

SD `=sqrt(npq )=sqrt(4 xx 15/32xx17/32)=sqrt(1020/1024)=sqrt(255/256)=0.998`