What are the mean and standard deviation of a binomial probability distribution with #n=88 # and #p=24/32 #?

Question

2474 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-04T10:25:09

#E(X)=66#

#sd=sqrt(22)#

for a Binomial distribution

#X~B(n,p)#

in this case

#X~B(88,24/32)#

or#" "X~B(88,3/4)#

mean#" "E(X)=np#

in this case

#E(X)=88xx3/4=66#

standard deviation =#sqrt"variance"#

#sd=sqrt(np(1-p))#

#sd=sqrt(66xx1/4)#

#sd=sqrt22#