# What are the mean and standard deviation of a binomial probability distribution with n=5  and p=1/32 ?

Nov 18, 2015

For the Binomial distribution ...

mean $= n p$
variance $= n p q$

#### Explanation:

mean $= n p = 5 \times \frac{1}{32} = \frac{5}{32}$

variance $= n p q = 5 \times \frac{1}{32} \times \left(1 - \frac{1}{32}\right) =$155/1024

standard deviation $= \sqrt{v a r i a n c e} = \sqrt{\frac{155}{1024}} \approx 0.389$