What are the points of discontinuity and vertical asymptote #(x^2 - 2x - 8)/(x + 6)#?
1 Answer
Jul 5, 2015
Vertical asymptote x= -6 and point of discontinuity is at x= -6
Explanation:
Vertical asymptote is x= -6 and the function is discontinuous at x=-6, because , then it becomes undefined.
